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Friday, May 29, 2026

MA25C02 |✏️ Vector Space| Example 3| it possible to write the vector (-2,0,3) as a linear combination |

Linear Combination – Example3
MA25C02 · Linear Algebra

Linear Combination of Vectors

N/D-25-R-21  |  Worked Example


Tutorial Video: Linear Combination & System of Equations
Linear Combinations Linear Span Linear Algebra Vector Space
Q

Is it possible to write the vector \((-2,\,0,\,3)\) as a linear combination of the two vectors \((1,3,0)\) and \((2,4,-1)\)? Justify.

Solution  
Given
\( u = (1,3,0), \quad v = (2,4,-1), \quad w = (-2,0,3) \)

Suppose \(w\) is a linear combination of \(u\) and \(v\). Then there exist scalars \(x, y\) such that \[ xu + yv = w. \] That is, \[ x(1,3,0) + y(2,4,-1) = (-2,\,0,\,3). \] Comparing components we get the system:

\( x + 2y = -2 \) — (1)
\( 3x + 4y = \phantom{-}0 \) — (2)
\( \phantom{3x +{}} {-y} = \phantom{-}3 \) — (3)

Solving equations (1) and (2) simultaneously:

From (1): \( x = -2 - 2y \) Substitute into (2): \( 3(-2-2y)+4y=0 \;\Rightarrow\; -6-6y+4y=0 \;\Rightarrow\; y=-3 \) Back-substitute: \( x = -2 - 2(-3) = -2+6 = 4 \) \( \therefore\; x = 4, \quad y = -3 \)
Verify in equation (3)
\( -y = -(-3) = 3 \;\checkmark \)
Equation (3) is satisfied.
Conclusion
Yes, \(w\) is a linear combination of \(u\) and \(v\).
Specifically,  \( 4u - 3v = w \).

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