Tutorial Video: Vector Spaces-Subspaces-Defintion
Vector Subspaces
Definition: Subspace
A subset \(W\) of a vector space \(V\) over a field \(F\) is called a subspace if \(W\) is itself a vector space under the same operations defined on \(V\).
Necessary Properties:
Necessary Properties:
- \(x + y \in W\) whenever \(x, y \in W\) (Additive Closure)
- \(\alpha x \in W\) whenever \(\alpha \in F, x \in W\) (Scalar Closure)
- \(W\) contains the zero vector \(\mathbf{0}\)
- Every vector in \(W\) has an additive inverse in \(W\)
Linear & Direct Sums
Linear Sum (\(W_1 + W_2\))
\[ W_1 + W_2 = \{ v \in V \mid v = w_1 + w_2, w_1 \in W_1, w_2 \in W_2 \} \]
Direct Sum (\(V = W_1 \oplus W_2\))
\(V\) is the direct sum of \(W_1\) and \(W_2\) if:
- \(V = W_1 + W_2\)
- \(W_1 \cap W_2 = \{ \mathbf{0} \}\)
Worked Examples
Question 1 A/M-25-R-21
Is the zero vector a subspace? Give reason.
Yes, the zero vector alone forms a subspace.
Reason:Let \(W = \{ \mathbf{0} \}\):
- \(W\) is non-empty (\(\mathbf{0} \in W\)).
- Closed under Addition: \(\mathbf{0} + \mathbf{0} = \mathbf{0} \in W\).
- Closed under Scalar: \(c \cdot \mathbf{0} = \mathbf{0} \in W\).
Question 2 N/D-24-R-21
Determine whether the set of vectors of the form \((a, b, 1)\) is a subspace of \(\mathbb{R}^3\).
Let \(W = \{ (a, b, 1) \mid a, b \in \mathbb{R} \}\)
Verification: To be a subspace, \(W\) must contain the zero vector \((0,0,0)\).
- In \(\mathbb{R}^3\), the zero vector is \((0,0,0)\).
- However, every vector in \(W\) has a fixed third component of 1.
- Therefore, \((0,0,0) \notin W\).
Conclusion: W is NOT a subspace of \(\mathbb{R}^3\).
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