Absolute Max & Min of a Cubic Function on a Closed Interval — Step-by-Step Calculus Example 11 Applications of Deriva...
Friday, August 21, 2026
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Tuesday, August 18, 2026
Absolute Max & Min of a Quartic Function on a Closed Interval | f(x) = 3x⁴ − 2x³ − 6x² + 6x + 1 | Example 10 | Differential Calculus
DINESH KUMAR M
August 18, 2026
Absolute Maximum and Minimum of f(x) = 3x⁴ − 2x³ − 6x² + 6x + 1 | Calculus Worked Example 10 Applications of Derivatives ...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Sunday, August 16, 2026
Absolute Maximum and Minimum of f(x) = log(x² + x + 1) | Calculus Worked Example 9 | Differential Calculus |
DINESH KUMAR M
August 16, 2026
Absolute Maximum and Minimum of f(x) = log(x² + x + 1) | Calculus Worked Example 9 Applications of Derivatives · Worked E...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Friday, August 14, 2026
Absolute Maximum and Minimum of f(x) = 3x⁴ − 4x³ − 12x² + 1 | Calculus Worked Example 8 | Differential Calculus |
DINESH KUMAR M
August 14, 2026
Absolute Maximum and Minimum of f(x) = 3x⁴ − 4x³ − 12x² + 1 | Calculus Worked Example 8 Applications of Derivatives · Wor...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Tuesday, August 11, 2026
Increasing, Decreasing Intervals & Extreme Values of f(x) = −x³ + 12x + 5 | Calculus Worked Example 7| Differential Calculus |
DINESH KUMAR M
August 11, 2026
Increasing, Decreasing & Extreme Values of f(x) = −x³ + 12x + 5 Applications of Derivatives · Worked Example 7 Where...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Sunday, August 9, 2026
Learn how to find local maxima, minima, and points of inflection for f(x) = x³ − 6x² + 9x + 1 using the second derivative test | Example 6 | Differential Calculus |
DINESH KUMAR M
August 09, 2026
Finding Maxima, Minima & Inflection Points — A Calculus Walkthrough Applied Calculus · Worked Example 6 Fi...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
Friday, August 7, 2026
Local Maximum and Minimum of y = x⁴ − 4x³ — Complete Solution Using the Second Derivative Test | Example 5 | Differential Calculus |
DINESH KUMAR M
August 07, 2026
Find Local Maximum and Minimum of y = x⁴ − 4x³ | Second Derivative Test | Engineering Mathematica En...
Labels
MA25C01,
MAX MIN ONE
Location:MADURAI
Madurai, Tamil Nadu, India
